Word problem help please?

How do you solve this problem?



Jack has a total of 155$ in $2 and $5 pizza coupons.If he has 40 coupons in all, how many of each kind does he have?



ThanksWord problem help please?
Let x = the # of $2 coupons

Let y= the # of $5 coupons

Now solve for x and y.



x+y=40

2x+5y=155



x+y=40 *(-2)



2x+5y= 155

-2x -2y = -80



3y =75

y=25



Plug the value of y in to find x.



x+25=40

x=15



Ans. 15 $2 coupons and 25 $5 coupons.
2x + 5y = 155

x + y = 40

15 2$ coupons

25 5$ couponsWord problem help please?
25 5$ coupons, 15 2$ coupons
anything that works in the equation 2x+5y=155Word problem help please?
x is the number of $2 ones

y is the number of $5 ones



x+y=40

2x+5y=155



x=40 - y



2(40 - y) + 5y=155



80 -2y + 5y=155



3y=75



y=25



25 $5 ones and 15 $2 ones
t = 2$ coupons, f = 5$ coupons



he has 40 coupons in all,



1) t + f = 40



f = 40 - t



total of 155$ in $2 and $5 pizza coupons



2) 2t + 5f = 155



2t + 5(40 - t) = 155 {substitute for f from equation 1}



2t + 200 - 5t = 155



- 3t = - 45



t = 15



1) f = 40 - 15 = 25



check



2) 2(15) + 25(5) = 155



30 + 125 = 155



155 = 155
2x+5y=155-------%26gt;Jack has a total of 155$ in $2 and $5 pizza coupons



x+y=40------------%26gt;he has 40 coupons in all





so,



y=40-x



now plug that into the first equation.



2x+5(40-x)=155



2x+200-5x=155



-3x=-45



x=15



now plug this number into the second equation



x+y=40



15+y=40



y=25



he has 25 $5 coupons and 15 $2 coupons