Can someone help with this math problem please.?

Heres the question.



Teresa is planning to order a pizza. She can choose between a coupon offer and the store special:

Coupon: $14 for a plain pizza

$0.50 per topping



Store Special: $11.50 for a plain pizza

$1 per topping



I need 2 equations to find the number of toppings that make the two choices the same price.Can someone help with this math problem please.?
It's 5 toppings per pizza.

For the first one. $.50 per topping

5 x $.50 = 2.50

14 + $2.50 = $16.50

The Second. $1 per topping

$1 x 5 = 5

$11.50 +$ 5 = $16.50
x=14+0.5x

x=11.50+1xCan someone help with this math problem please.?
make two algebraic expressions and set them equal to eachother



14+.5x = 11.5+x



solve



x=5 toppings



:)
Okay. y will equal the total cost of the pizza while x will equal the number of toppings.



Coupon: y = .5x + 14 (the cost of the plain pizza)



Store special: y= x + 11.5 (the cost of the plain pizza)



To find the same price, since the total cost of the pizzas need to be the same, you can set the two equations on either side of the equal sign.

So,

.5x + 14 = x + 11.5



And I think you can simplify from there. :)Can someone help with this math problem please.?
Start by formulating equations for the two deals:



coupon: 14 + 0.5 * T = P

special: 11.5 + 1 * T = P



Where T is the number of toppings and P is the total price. Now solve for T:



coupon: T = (P - 14) / 0.5

special: T = (P - 11.5) / 1



So now you can plug in any price and get the number of toppings for each deal. For instance a $20.5 pizza would be:



coupon: (20.5 - 14) / 0.5 = 13 toppings

special: (20.5 - 11.5) / 1 = 9 toppings
The two equations you need are:



(I) $14 + (.50)*T



(II) $11.50 + $1*T



Set (I) = (II) and solve for T.
The store special: $11.50 for plain with $1 topping -

4 toppings, $1 each=$4 + $11.50 for pizza = $15.50.



Coupon $14 and $.50 for topping =

l plain pizza $14 + 3 toppings = $15.50.
14 + .5x = Total (T)

11.50 + (1)x = T

and X is the number of toppings



T = T ....therefore



14 + .5x = 11.50 + x

subtract 11.50 both sides

2.5 + .5x = x

subtract .5x from both sides

2.5 = .5x

multiply by 2

x = 5



at 5 toppings - both pizzas cost the same price



all the best